Let consecutive numbers be, x, x+1 and x+2.According to the condition, we have          x + [x+1] +[x+2] =51or                x + x + 1 + x + 2 =51or                              3x + 3 = 51   Transposing 3 to RHS, we have                                3x = 51 - 3 = 48  Dividing both sides by 3, we have:                                  or  x =16Now                         x + 1 = 16 + 1 = 17and                          x + 2 = 16 + 2 =18        Thus, the required three consecutive numbers are: 16, 17 and 18.